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Quizzes > High School Quizzes > Science

Motion Practice Quiz Worksheet

Sharpen motion skills with engaging practice tests

Difficulty: Moderate
Grade: Grade 8
Study OutcomesCheat Sheet
Paper art depicting a fun, interactive high school physics quiz on motion concepts.

Which of the following best describes speed?
Change in displacement
Distance traveled per unit time
Total distance traveled
Rate of change of velocity
Speed is defined as the distance traveled per unit of time. It is a scalar quantity, meaning it does not have an associated direction.
What distinguishes velocity from speed?
Velocity only applies to straight-line motion, unlike speed.
Velocity includes direction, while speed does not.
Velocity is measured in kilometers, while speed is measured in seconds.
Velocity is always greater than speed.
Velocity is a vector quantity that includes both magnitude and direction, unlike speed which is a scalar. This distinction is essential in analyzing motion.
What is acceleration in physics?
The rate of change of speed only.
The total distance covered in a given time period.
The change in velocity over time.
The effect of friction on a moving object.
Acceleration is defined as the rate at which velocity changes over time. Since velocity is a vector, acceleration is also a vector with both magnitude and direction.
Which option best defines displacement?
The overall duration of motion.
The total path length traveled by an object.
The straight-line distance in a specified direction from the starting point.
The change in speed over time.
Displacement is a vector quantity that refers to the change in position from the starting point to the ending point, including direction. It differs from distance, which is the total path length traveled.
A car travels 100 km in 2 hours. What is its average speed?
200 km/h
25 km/h
50 km/h
100 km/h
Average speed is calculated by dividing the total distance traveled by the total time taken. Here, 100 km divided by 2 hours results in an average speed of 50 km/h.
A runner starts from rest and accelerates uniformly at 2 m/s². How long does it take to reach a speed of 10 m/s?
5 seconds
4 seconds
8 seconds
6 seconds
Using the formula v = u + at (with u = 0), substituting the known values gives 10 m/s = 2 m/s² × t, resulting in t = 5 seconds.
A car's speed increases from 30 km/h to 90 km/h in 10 seconds. What is its acceleration in m/s²?
1.67 m/s²
5.0 m/s²
2.5 m/s²
3.0 m/s²
First convert km/h to m/s: 30 km/h is approximately 8.33 m/s and 90 km/h is about 25 m/s. The acceleration is calculated as (25 m/s - 8.33 m/s) / 10 s, which is approximately 1.67 m/s².
A ball is thrown vertically upward with an initial velocity of 20 m/s. Assuming the acceleration due to gravity is 10 m/s², how long does it take to reach the highest point?
4 seconds
1 second
5 seconds
2 seconds
At the highest point, the ball's velocity is zero. Using the formula v = u - gt and substituting the given values (0 = 20 m/s - 10 m/s² × t) shows that t = 2 seconds.
Which of the following best represents a uniformly accelerating object's velocity-time graph?
A parabolic curve
A sinusoidal wave
A straight line with a constant slope
A horizontal line
Uniform acceleration means the velocity increases at a constant rate, producing a linear relationship between velocity and time. Therefore, the appropriate graph is a straight line with a constant slope.
A car travels at 60 km/h for 2 hours and then at 90 km/h for 1 hour. What is its average speed for the entire journey?
65 km/h
75 km/h
70 km/h
80 km/h
The total distance is (60 km/h × 2 hours) + (90 km/h × 1 hour) = 210 km, and the total time is 3 hours. Dividing the total distance by the total time gives an average speed of 70 km/h.
What is the approximate acceleration due to gravity on Earth?
9.8 km/s²
10 m/s²
9.8 m/s²
8.9 m/s²
The acceleration due to gravity near Earth's surface is approximately 9.8 m/s². This constant is used in calculations involving free-fall and other motion-based problems.
A cyclist travels at a constant speed of 5 m/s for 10 seconds. What is the displacement of the cyclist?
60 meters
55 meters
50 meters
45 meters
Since the cyclist is moving at a constant speed, displacement is calculated as speed multiplied by time. Therefore, 5 m/s × 10 s equals 50 meters.
Which of the following scenarios best illustrates uniform motion?
A car accelerating from a stoplight
A car moving at a constant speed on a straight road
A ball thrown upward slowing down then falling
A runner speeding up gradually
Uniform motion is characterized by motion at a constant speed in a straight line. A car moving steadily on a straight road is a clear example of uniform motion.
A ball rolling down a smooth ramp from rest accelerates uniformly. Which term best describes its motion?
Uniform circular motion
Simple harmonic motion
Constant speed motion
Uniformly accelerated motion
Since the ball starts at rest and accelerates at a constant rate down the ramp, its motion is described as uniformly accelerated. This indicates that its velocity increases linearly with time.
In a distance-time graph, what does a steeper slope indicate?
A longer time interval
A higher speed
A lower acceleration
A larger displacement
The slope of a distance-time graph represents the speed of an object. A steeper slope means more distance is covered in a given time, indicating a higher speed.
A car traveling at 20 m/s applies brakes and decelerates at a constant rate of 5 m/s² until it stops. How far does the car travel during braking?
20 meters
60 meters
50 meters
40 meters
Using the kinematic equation v² = u² + 2as with v = 0, we have 0 = (20 m/s)² + 2(-5 m/s²)s, which simplifies to s = 40 meters. This distance is how far the car travels before stopping.
A projectile is launched horizontally from a 45-meter-high platform with an initial speed of 10 m/s. Assuming g = 10 m/s², how long does it take to hit the ground?
4.5 seconds
2 seconds
3 seconds
6 seconds
The vertical drop is independent of the horizontal speed. Using the formula h = 0.5 × g × t², with h = 45 m and g = 10 m/s², t calculates to 3 seconds.
A motorcyclist rides around a circular track with a radius of 50 m at a constant speed of 20 m/s. What is the magnitude of the centripetal acceleration?
10 m/s²
8 m/s²
20 m/s²
4 m/s²
Centripetal acceleration is given by the formula a = v²/r. Substituting v = 20 m/s and r = 50 m yields a = (20²)/50 = 400/50 = 8 m/s².
A cyclist accelerates from rest at a rate of 0.5 m/s². How far does the cyclist travel in 16 seconds?
32 meters
128 meters
80 meters
64 meters
Using the equation s = 0.5 × a × t² with the cyclist starting from rest, substituting a = 0.5 m/s² and t = 16 s gives s = 0.5 × 0.5 × (16²) = 64 meters.
An object covers 100 meters in the first 5 seconds and 150 meters in the next 5 seconds while moving along a straight line. What is the object's overall average speed?
35 m/s
30 m/s
20 m/s
25 m/s
The total distance traveled is 100 m + 150 m = 250 m over a total time of 10 seconds, yielding an average speed of 250 m / 10 s = 25 m/s.
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Study Outcomes

  1. Understand the basic principles of one-dimensional motion.
  2. Apply equations of motion to solve real-world problems.
  3. Analyze motion graphs to interpret displacement, velocity, and acceleration.
  4. Calculate distance, speed, and acceleration in various scenarios.
  5. Evaluate and predict motion outcomes using fundamental physics concepts.

Worksheet About Motion Cheat Sheet

  1. Understand Newton's Three Laws of Motion - Kickstart your physics journey by learning how objects react to forces, from resting peacefully to zooming away. Get to know how inertia keeps things still, how F = ma drives acceleration, and why every action sparks an equal and opposite reaction in roller coasters and rocket launches alike. Read more
  2. Master the Kinematic Equations - Motion becomes your playground when you connect displacement, velocity, acceleration, and time with three core formulas. Whether you're timing a sprinter or launching a paper airplane, v = v₀+at, s = s₀+v₀t+½at², and v² = v₀²+2a(s−s₀) are your secret weapons. Read more
  3. Grasp the Concept of Acceleration - Acceleration tells the story of how quickly your speed changes, calculated as a = ( vₙ - vᵢ )/t. Feel the thrill of understanding why a race car's velocity shoots up faster than a tricycle's, and how time slices shape every stunt, skid, and sprint. Read more
  4. Analyze Projectile Motion - When you toss a ball or fire a cannon, horizontal speed stays steady while gravity pulls you down in a graceful parabola. Use x = v₀ₓ·t and y = v₀ᵧ·t - ½gt² to predict where your water balloon will land - perfect for friendly backyard competitions. Read more
  5. Explore Uniform Circular Motion - Spinning a rock on a string or riding a merry-go-round introduces centripetal acceleration, always pointing to the center. Calculate aₙ = v²/r to see why faster speeds or tighter turns feel more thrilling - and why satellites stay in orbit. Read more
  6. Understand Force, Mass & Acceleration - Newton's Second Law, F = ma, is the ultimate cheat code: push harder or lighten the load to boost acceleration. It's why pushing an empty cart is easier than a full one, and how engineers design powerful rockets. Read more
  7. Learn About Momentum and Impulse - Momentum (p = mv) tracks how much "oomph" an object has, while impulse (F·Δt) measures how forces change that oomph. From bumper cars to batting practice, mastering these ideas keeps you safe and scoring high. Read more
  8. Study Energy Conservation in Motion - Kinetic energy (KE = ½mv²) and potential energy swap roles like a thrilling tag team, but their total stays constant without friction. Watch roller coasters trade height for speed, and learn why energy never vanishes - only transforms. Read more
  9. Examine Friction and Air Resistance - Friction (f = μN) and air resistance put the brakes on motion, turning sleights into skids and turbo runs into gentle cruises. Discover how surface texture and speed shape every slide, skid, and drag race finish line. Read more
  10. Practice Real-World Problem Solving - Glue all these concepts together by tackling challenges like stopping distances, catapult ranges, and circuit board vibrations. Active problem-solving turns theory into "aha!" moments and prepares you for epic physics victories. Read more
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