Quiz sur les Maths: Practice Test

Dividing 15 by 3 gives 5. This demonstrates a basic division operation, reinforcing fundamental arithmetic skills.

Adding 7 and 9 gives 16. This simple addition problem helps reinforce basic arithmetic skills.

Subtracting 8 from 20 results in 12. This problem emphasizes the basic concept of subtraction.

Multiplying 4 by 6 gives 24. This question reinforces multiplication skills by applying basic number facts.

Subtracting 3 from 10 gives 7 and adding 2 results in 9. This problem reinforces the order of operations in basic arithmetic.

Multiplying 20 by 3/4 gives 15. This question tests understanding of basic fraction multiplication.

By combining like terms, 2x and 3x add up to 5x. This reinforces the concept of adding algebraic expressions.

Dividing both sides of the equation 2x = 14 by 2 yields x = 7. This problem assesses the ability to solve basic linear equations.

The area of a rectangle is calculated as length multiplied by width, so 8 cm × 5 cm equals 40 cm². This reinforces the application of geometric formulas.

The decimal 0.5 is exactly equivalent to the fraction 1/2. This question helps bridge understanding between decimals and fractions.

Since 25% is equivalent to 25/100, it simplifies to 1/4 by dividing numerator and denominator by 25. This reinforces percentage conversion and simplification.

The ratio indicates that for every 2 blue marbles, there are 3 red marbles. With 10 blue marbles (which is 5 times 2), the number of red marbles is 5 × 3, equaling 15.

A square's perimeter is calculated as 4 times its side length, so 4 × 6 cm equals 24 cm. This solidifies the concept of perimeter calculation.

Since 100 centimeters equal 1 meter, 150 centimeters is equal to 1.5 meters. This problem reinforces basic unit conversion skills.

Adding 4 to both sides of the equation gives 3y = 15, and dividing by 3 results in y = 5. This reinforces the process of solving linear equations.

First expand the left side to get 3x - 12 and then subtract 2x from both sides, resulting in x - 12 = 6. Adding 12 to both sides reveals that x = 18.

The sum of the ratio parts is 2 + 3 + 4 = 9. Dividing the total triangle angle sum (180°) by 9 gives 20°, so the largest angle is 4 × 20° = 80°.

Increasing each side by 50% makes the new side 1.5 times longer. Since area is proportional to the square of the side length, the new area is (1.5)² = 2.25 times the original area, which indicates a 125% increase.

The number 91 can be factored into 7 and 13. Since 7 is the smaller of the two prime factors, it is the correct answer.

A 20% discount lowers the price to 80% of the original, and a subsequent 10% discount on the reduced price subtracts an additional 8% (10% of 80%), resulting in 72% of the original price. This problem illustrates sequential percentage discounts.