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Quizzes > High School Quizzes > Mathematics

Chapter 2 Precalculus Practice Test

Practice crucial precalculus skills for exam success.

Difficulty: Moderate
Grade: Grade 11
Study OutcomesCheat Sheet
Colorful paper art promoting the Chapter 2 Precalc Challenge for high school students.

Which of the following best describes a function?
A relation where outputs can have multiple corresponding inputs.
A relation in which every input is associated with exactly one output.
A relationship between variables with no specific rules.
A set of isolated points.
A function is defined as a relation where each input corresponds to exactly one output. This property distinguishes functions from general relations that might associate an input with more than one output.
What is the domain of f(x) = √x?
x ≤ 0
x > 0
All real numbers
x ≥ 0
The square root function is only defined for non-negative values since the square root of a negative number is not a real number. Therefore, the domain of √x is x ≥ 0.
If f(x) = x + 3, what is f(2)?
5
6
2
3
To evaluate the function f(x) = x + 3 at x = 2, substitute 2 into the function to get 2 + 3, which equals 5. This demonstrates basic function evaluation.
Which of the following is a quadratic function?
f(x) = 2x + 3
f(x) = x² + 2x + 1
f(x) = √x
f(x) = 1/x
A quadratic function is typically defined as a second-degree polynomial in the form ax² + bx + c with a ≠ 0. The function f(x) = x² + 2x + 1 fits this definition, making it quadratic.
What is the general form of a linear function?
f(x) = ax² + bx + c
f(x) = a/x + b
f(x) = mx + b
f(x) = a^x
A linear function is generally expressed in the form f(x) = mx + b, where m is the slope and b is the y-intercept. This form produces a straight line when graphed.
Find the domain of f(x) = 1/(x - 4).
x < 4
x can be any real number
x > 4
x ≠ 4
The function 1/(x - 4) is undefined when the denominator equals zero. Setting x - 4 = 0 yields x = 4, which must be excluded from the domain.
Solve for x: 2^x = 16.
16
4
8
2
Since 16 can be expressed as 2^4, the equation 2^x = 16 implies x must equal 4. This relies on understanding the properties of exponents.
If f(x) = 2x - 3 and g(x) = x², what is (f ∘ g)(2)?
5
9
1
7
To find (f ∘ g)(2), first calculate g(2) which is 2² = 4. Then evaluate f(4): 2 × 4 - 3 = 5.
Determine the vertex of the parabola y = -x² + 4x - 3.
(2, -1)
(2, 1)
(-2, 1)
(-2, -1)
The vertex of a parabola defined by y = ax² + bx + c is found using the formula x = -b/(2a). For a = -1 and b = 4, x = 2, and substituting back gives y = 1. Thus, the vertex is (2, 1).
Which transformation does the graph of y = f(x - 2) + 3 represent compared to y = f(x)?
Shift right by 2 units and up by 3 units
Shift left by 2 units and up by 3 units
Shift right by 2 units and down by 3 units
Shift left by 2 units and down by 3 units
Replacing x with x - 2 in the function shifts the graph horizontally to the right by 2 units. Adding 3 shifts it vertically upward by 3 units, combining to form the given transformation.
Solve the logarithmic equation: log₂(x) = 3.
2
3
6
8
The equation log₂(x) = 3 means that 2³ = x. Since 2³ equals 8, x must be 8. This uses the basic definition of logarithms.
Simplify: log(a * b) where a > 0 and b > 0.
log(a/b)
log(a) * log(b)
log(a) - log(b)
log(a) + log(b)
One of the fundamental properties of logarithms is that the log of a product is the sum of the logs. Therefore, log(a * b) simplifies to log(a) + log(b).
Find the inverse of the function f(x) = 3x - 5.
(x + 5)/3
(x - 5)/3
3x + 5
5 - 3x
To find the inverse of f(x) = 3x - 5, swap x and y to obtain x = 3y - 5 and then solve for y. The solution y = (x + 5)/3 gives the inverse function.
Determine the amplitude of the sine function y = 5 sin(x).
5
1/5
0
10
The amplitude of a sine function is the absolute value of the coefficient in front of sin(x). In y = 5 sin(x), the coefficient is 5, so the amplitude is 5.
If f(x) = x² and g(x) = √x, what is (f ∘ g)(x) for x ≥ 0?
√x
√(x²)
x
The composition (f ∘ g)(x) means f(g(x)). Given g(x) = √x, applying f gives (√x)², which simplifies to x as long as x is non-negative. This illustrates function composition and domain consideration.
Determine the horizontal and vertical asymptotes of the function f(x) = (2x² + 3)/(x² - 1).
Horizontal asymptote y = 0; vertical asymptote x = 0
Horizontal asymptote y = 2; no vertical asymptote
Horizontal asymptote y = 2; vertical asymptotes x = 1 and x = -1
No horizontal asymptote; vertical asymptote x = 1
For rational functions where the degrees of the numerator and denominator are equal, the horizontal asymptote is the ratio of the leading coefficients (2/1 = 2). Vertical asymptotes occur where the denominator equals zero, which happens at x = 1 and x = -1.
Solve the inequality x² - 5x + 6 < 0.
2 < x < 3
x < 0
x < 2 or x > 3
x > 2 and x < 5
Factoring the quadratic gives (x - 2)(x - 3) < 0. The product of two factors is negative when one is positive and the other is negative, which occurs when x is between 2 and 3.
Determine the period of the function y = cos(4x).
π
π/2
π/4
The period of a cosine function in the form cos(Bx) is given by 2π/B. Here, B is 4, so the period is 2π/4 = π/2.
Find the sum of the arithmetic series: 2, 5, 8, ..., 29.
155
160
145
150
The series increases by a common difference of 3. Calculating the number of terms using n = ((last term - first term)/difference) + 1 gives 10 terms, and applying the sum formula S = n/2 × (first term + last term) results in 155.
Given the exponential function f(x) = 3e^(2x), find its derivative f'(x).
6e^(2x)
3e^(2x)
6e^(x)
2e^(2x)
Using the chain rule to differentiate f(x) = 3e^(2x), the derivative of e^(2x) is 2e^(2x). Multiplying by the constant 3 gives f'(x) = 6e^(2x). This demonstrates the application of the chain rule.
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Study Outcomes

  1. Analyze function properties and transformations for various types of functions.
  2. Evaluate polynomial and rational functions to determine their behavior and intercepts.
  3. Simplify and solve exponential and logarithmic equations in different contexts.
  4. Solve trigonometric equations and interpret their graphs accurately.
  5. Apply problem-solving strategies to address key precalculus challenges.

Chapter 2 Precalculus Test Cheat Sheet

  1. Understand the Pythagorean Theorem - The Pythagorean Theorem is your right”triangle superhero: it states that a² + b² = c² where c is the hypotenuse. Sketch some triangles and plug in your own numbers to watch this relationship in action. Once you've got it down, no right triangle will ever stump you again! Yoshiwara Math Trig Summary
  2. Master Trigonometric Ratios - Think of sine, cosine, and tangent as the ultimate angle cheat codes: sin(θ)=opposite/hypotenuse, cos(θ)=adjacent/hypotenuse, and tan(θ)=opposite/adjacent. Use mnemonic devices like SOH‑CAH‑TOA to lock them in your brain for good. With these ratios, you'll decode any right triangle like a math detective! Yoshiwara Math Trig Summary
  3. Learn Exact Values for Special Angles - Certain angles like 30°, 45°, and 60° have neat exact values (e.g., sin 30°=½, cos 45°=√2/2, tan 60°=√3) that you can memorize. Flashcards or a quick sketch of the unit circle can turn these facts into muscle memory. Soon you'll know them instantly instead of pulling out your calculator every time! Yoshiwara Math Trig Summary
  4. Practice Solving Quadratics by Factoring - Turn your quadratic into a zero by moving everything to one side, then break it into two binomials. Look for pairs that multiply to c and add to b, then set each factor to zero to find your solutions. It's like solving a puzzle - once you spot the right pieces, the answer just clicks into place. Symbolab Precalculus Guide
  5. Utilize the Quadratic Formula - When factoring feels impossible, the quadratic formula x = ( - b ± √(b² - 4ac)) / (2a) rides to the rescue. Just plug in a, b, and c, and you'll unveil your roots every time. Memorize it like a superhero motto so you're always ready for any quadratic crisis! Symbolab Precalculus Guide
  6. Understand the Discriminant - The discriminant, b² - 4ac, is your quadratic's mood ring: positive means two real roots, zero means one repeated root, and negative means you'll dive into complex territory. Checking it first saves you from endless guesswork on whether you'll need real or complex solutions. It's like peeking at the answers before the big test! Symbolab Precalculus Guide
  7. Learn About Complex Numbers - Complex numbers introduce i, where i² = - 1, and let you combine real and imaginary parts as a + bi. Get comfortable adding, subtracting, and multiplying these numbers - you'll feel like you're bending math rules! Embracing complex numbers opens the door to advanced topics like signal processing and quantum mechanics. OER Commons Algebra Maps
  8. Practice Simplifying Radical Expressions - Simplifying radicals is all about combining like terms and ditching pesky roots from the denominator. Factor out squares, rationalize whenever needed, and watch your expressions shrink. Before long, radicals will feel less like monsters and more like friendly puzzles! OER Commons Algebra Maps
  9. Understand Function Transformations - Shifting, stretching, and reflecting functions lets you morph y = f(x) into all sorts of wild shapes. Practice horizontal shifts, vertical stretches, and reflections to see how each tweak affects the graph. Master these moves and you can sketch any transformed function in seconds! UMN Precalculus Transformations
  10. Familiarize Yourself with Sine & Cosine Graphs - Get cozy with amplitude, period, and phase shifts to draw precise sine and cosine curves. Experiment by plugging different values into y = A sin(Bx + C) or y = A cos(Bx + C) and watch the wave dance. These functions underpin everything from sound waves to tides, so understanding them pays off big time! UMN Precalculus Sine & Cosine
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