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Physics Forces Addition Quiz Challenge

Test Your Vector Addition and Force Skills

Difficulty: Moderate
Questions: 20
Learning OutcomesStudy Material
Colorful paper art representing a Physics Forces Addition Quiz.

Ready to explore vector addition in physical systems? This Physics Forces Addition Quiz is perfect for students and educators looking to test net force understanding with engaging multiple-choice challenges. The quiz covers real-world scenarios to sharpen analytical skills and deepen comprehension of force vectors. It can be freely modified in our editor, so teachers can customize questions to suit their lesson plans. For more practice, try the Physics Mechanics Practice Quiz or challenge yourself with the Physics Quiz on Force and Motion, and browse additional quizzes!

What is the resultant of two colinear forces of 8 N to the right and 3 N to the left?
11 N to the left
5 N to the right
5 N to the left
11 N to the right
Opposing forces subtract: 8 N âˆ' 3 N = 5 N directed to the right. This gives the net force direction and magnitude.
Two forces of 10 N east and 6 N east act on an object. What is the resultant?
6 N west
4 N east
16 N east
10 N north
Forces in the same direction add directly: 10 N + 6 N = 16 N east. There is no component perpendicular to east.
A 3 N north force and a 4 N east force act on a point. What is the magnitude of the resultant?
7 N
5 N
12 N
1 N
Perpendicular vectors combine by Pythagoras: √(3² + 4²) = 5 N. The resultant is 5 N in a northeast direction.
Which graphical method is used to find the resultant of two vectors?
Tip-to-tip method
Reflection method
Head-to-tail method
Offset method
The head-to-tail method places the tail of each vector at the head of the previous one and draws the resultant from the first tail to the last head. Other methods listed are not standard.
A body is subjected to forces of 7 N north and 7 N south. What is the net force?
7 N south
7 N north
14 N north
0 N
Equal and opposite forces cancel out, giving a net force of zero. The body is in translational equilibrium.
What is the horizontal component of a 10 N force acting at 30° above the horizontal?
3.46 N
10 N
8.66 N
5 N
Horizontal component = 10 N à - cos 30° ≈ 10 à - 0.866 = 8.66 N. Cosine projects the force onto the horizontal axis.
Two perpendicular forces, 5 N along the x-axis and 12 N along the y-axis, act on a point. What is the magnitude of the resultant?
12 N
7 N
13 N
√169 N
Since the forces are orthogonal, the resultant = √(5² + 12²) = 13 N by the Pythagorean theorem.
Two forces of 8 N east and 6 N north act on an object. To achieve equilibrium, what must be the third force?
14 N at 225°
4 N at 270°
10 N at 216.87°
10 N at 45°
Resultant of the two is 10 N at 36.87°. The equilibrant is equal in magnitude but opposite in direction: 10 N at 36.87° + 180° = 216.87°.
What is the angle of the resultant force with components Fx = 6 N and Fy = 8 N, measured from the positive x-axis?
36.87°
126.87°
90°
53.13°
Angle = arctan(Fy/Fx) = arctan(8/6) ≈ 53.13°. Both components are positive, placing the resultant in the first quadrant.
Which set of three forces will keep a particle in equilibrium?
10 N at 0°, 10 N at 90°, 10 N at 180°
5 N at 0°, 5 N at 120°, 5 N at 240°
8 N at 0°, 8 N at 45°, 8 N at 90°
6 N at 0°, 6 N at 60°, 6 N at 120°
Three equal magnitude forces separated by 120° form a closed triangle and sum to zero, resulting in equilibrium.
Find the magnitude of the resultant of 20 N at 0°, 15 N at 90°, and 25 N at 180°.
30 N
15.81 N
40 N
10 N
Sum components: x = 20 âˆ' 25 = âˆ'5 N, y = 15 N. Magnitude = √((-5)² + 15²) ≈ 15.81 N.
What is the resultant magnitude of two forces: 8 N at 30° and 6 N at 150°?
7.21 N
2 N
10 N
14 N
Compute each force's components, sum them, and apply Pythagoras; the resultant is approximately 7.21 N.
What is the x-component of a 25 N force acting at 135°?
-17.68 N
25 N
17.68 N
-25 N
x-component = 25 N à - cos 135° = 25 à - (âˆ'0.707) ≈ âˆ'17.68 N. The negative sign indicates leftward direction.
What is the y-component of a 40 N force acting at 300°?
20 N
34.64 N
-20 N
-34.64 N
y-component = 40 N à - sin 300° = 40 à - (âˆ'0.866) ≈ âˆ'34.64 N. The negative sign indicates downward direction.
Three forces of equal magnitude 20 N act at angles 0°, 120°, and 240°. What is the net force?
34.64 N
10 N
0 N
20 N
Three vectors of equal magnitude spaced by 120° form a closed polygon, summing to zero net force.
A particle is acted upon by forces 15 N at 18°, 20 N at 110°, and 10 N at 243°. What is the magnitude of the resultant force?
5 N
14.73 N
20 N
30 N
Compute each force's components, sum them, then apply Pythagorean theorem to find √(2.887² + 14.445²) ≈ 14.73 N.
Determine the magnitude and direction of the equilibrant force that balances 12 N at 45° and 18 N at 135°.
21.63 N at 101.31°
21.63 N at 281.31°
30 N at 270°
12 N at 225°
Sum the given forces' components, then take the opposite vector for equilibrium. This yields ≈21.63 N at 281.31°.
What is the resultant of two forces, each 30 N in magnitude, with an angle of 120° between them?
0 N
51.96 N
60 N
30 N
By the law of cosines: √(30² + 30² âˆ' 2·30·30·cos 120°) = √(1800 + 900) = 30 N.
A 50 N force acts at 20° above the horizontal. What is its component along an axis rotated 30° above the horizontal?
43.30 N
25 N
49.24 N
50 N
Component along rotated axis = 50 N à - cos(20° âˆ' 30°) = 50 à - cos(âˆ'10°) ≈ 49.24 N.
In a force triangle, two sides are 20 N and 30 N with an included angle of 70°. What is the magnitude of the third side?
10 N
50 N
29.83 N
25 N
Law of cosines: √(20² + 30² âˆ' 2·20·30·cos 70°) ≈ 29.83 N gives the closing side of the triangle.
0
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Learning Outcomes

  1. Apply vector addition to calculate resultant forces
  2. Analyse multiple force systems for equilibrium
  3. Demonstrate understanding of force components
  4. Identify angles and magnitudes in force vectors
  5. Evaluate net force effects in varied scenarios

Cheat Sheet

  1. Forces Are Vectors! - Think of forces as unstoppable arrows with both strength and direction, ready to show you exactly what they'll do. By treating them as vectors, you can plot them on graphs and plug them into formulas to see how they combine in the real world. Vectors and Direction
  2. Head-to-Tail Addition - It's like a game of connect-the-dots with vector arrows: place the tail of one force at the head of another to reveal the combined effect. This visual trick instantly uncovers the mysterious "resultant force" hiding in your diagram. Vector Addition
  3. Component Breakdown - Break each force into horizontal and vertical buddies so you can tackle them one at a time. This strategy turns a messy vector party into two simple number lines you can manage like a pro. Component Addition
  4. Pythagorean Power - When your force components are perpendicular, the Pythagorean theorem becomes your best friend to find the hypotenuse - or resultant force. It's the classic a² + b² = c² trick that never fails in right-angle vector puzzles. Component Addition
  5. Trig to the Rescue - Sine, cosine, and tangent aren't just fancy words - they connect your triangle's sides to its angles, letting you pinpoint force directions with laser precision. Master these functions, and you'll always know which way the resultant arrow points. Component Addition
  6. Equilibrium Explained - When all the forces balance out and the net force hits zero, your object chills without accelerating - hello, static and dynamic balance! Understanding this calm state is key in everything from bridges to roller coasters. Equilibrium and Statics
  7. Resolution Practice - Break down those tricky angled forces into easy components over and over until it feels like second nature. This hands-on skill is the secret sauce for analyzing any multi-force situation. Resolution of Forces
  8. Angle & Magnitude Mastery - Sharpen your protractor skills and nail down each vector's angle and strength to avoid calculation slip-ups. Precision in measurement means confidence in your physics solutions. Vector Components
  9. Net Force Detective - Put on your investigator hat and combine all acting forces to uncover the true resultant that dictates motion. Predicting how objects behave under multiple pushes and pulls becomes an adventure in logical deduction. Addition of Forces
  10. Commutative Charm - Good news: the order you add vectors doesn't change the result thanks to the commutative property! Shuffle those arrows around without fear, and focus on the math instead of the order. Vector Addition
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